X^2+14x=38

Solution for X^2+14x=38 equation:

X^2+14X=38

We move all terms to the left:

X^2+14X-(38)=0

a = 1; b = 14; c = -38;
Δ = b2-4ac
Δ = 142-4·1·(-38)
Δ = 348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{348}=\sqrt{4*87}=\sqrt{4}*\sqrt{87}=2\sqrt{87}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{87}}{2*1}=\frac{-14-2\sqrt{87}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{87}}{2*1}=\frac{-14+2\sqrt{87}}{2}
$